X^2+1.3x-0.3=0

Solution for X^2+1.3x-0.3=0 equation:

X^2+1.3X-0.3=0

a = 1; b = 1.3; c = -0.3;
Δ = b2-4ac
Δ = 1.32-4·1·(-0.3)
Δ = 2.89
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.3)-\sqrt{2.89}}{2*1}=\frac{-1.3-\sqrt{2.89}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.3)+\sqrt{2.89}}{2*1}=\frac{-1.3+\sqrt{2.89}}{2}
$